PRP in base 79 and 83 For (27^n-25^n)/2, I found hitherto: (27^3-25^3)/2 (27^17-25^17)/2 (27^61-25^61)/2 (27^2777-25^2777)/2 (27^18211-25^18211)/2 (27^20183-25^20183)/2=(3^60549-5^40366)/2
To be completed...